3.89 \(\int \frac {\sin ^5(a+b x)}{\sqrt {d \tan (a+b x)}} \, dx\)

Optimal. Leaf size=107 \[ -\frac {d \sin ^5(a+b x)}{5 b (d \tan (a+b x))^{3/2}}-\frac {7 d \sin ^3(a+b x)}{30 b (d \tan (a+b x))^{3/2}}+\frac {7 \sin (a+b x) E\left (\left .a+b x-\frac {\pi }{4}\right |2\right )}{20 b \sqrt {\sin (2 a+2 b x)} \sqrt {d \tan (a+b x)}} \]

[Out]

-7/20*(sin(a+1/4*Pi+b*x)^2)^(1/2)/sin(a+1/4*Pi+b*x)*EllipticE(cos(a+1/4*Pi+b*x),2^(1/2))*sin(b*x+a)/b/sin(2*b*
x+2*a)^(1/2)/(d*tan(b*x+a))^(1/2)-7/30*d*sin(b*x+a)^3/b/(d*tan(b*x+a))^(3/2)-1/5*d*sin(b*x+a)^5/b/(d*tan(b*x+a
))^(3/2)

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Rubi [A]  time = 0.13, antiderivative size = 107, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {2598, 2601, 2572, 2639} \[ -\frac {d \sin ^5(a+b x)}{5 b (d \tan (a+b x))^{3/2}}-\frac {7 d \sin ^3(a+b x)}{30 b (d \tan (a+b x))^{3/2}}+\frac {7 \sin (a+b x) E\left (\left .a+b x-\frac {\pi }{4}\right |2\right )}{20 b \sqrt {\sin (2 a+2 b x)} \sqrt {d \tan (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Int[Sin[a + b*x]^5/Sqrt[d*Tan[a + b*x]],x]

[Out]

(-7*d*Sin[a + b*x]^3)/(30*b*(d*Tan[a + b*x])^(3/2)) - (d*Sin[a + b*x]^5)/(5*b*(d*Tan[a + b*x])^(3/2)) + (7*Ell
ipticE[a - Pi/4 + b*x, 2]*Sin[a + b*x])/(20*b*Sqrt[Sin[2*a + 2*b*x]]*Sqrt[d*Tan[a + b*x]])

Rule 2572

Int[Sqrt[cos[(e_.) + (f_.)*(x_)]*(b_.)]*Sqrt[(a_.)*sin[(e_.) + (f_.)*(x_)]], x_Symbol] :> Dist[(Sqrt[a*Sin[e +
f*x]]*Sqrt[b*Cos[e + f*x]])/Sqrt[Sin[2*e + 2*f*x]], Int[Sqrt[Sin[2*e + 2*f*x]], x], x] /; FreeQ[{a, b, e, f},
x]

Rule 2598

Int[((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> -Simp[(b*(a*Sin[
e + f*x])^m*(b*Tan[e + f*x])^(n - 1))/(f*m), x] + Dist[(a^2*(m + n - 1))/m, Int[(a*Sin[e + f*x])^(m - 2)*(b*Ta
n[e + f*x])^n, x], x] /; FreeQ[{a, b, e, f, n}, x] && (GtQ[m, 1] || (EqQ[m, 1] && EqQ[n, 1/2])) && IntegersQ[2
*m, 2*n]

Rule 2601

Int[((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[(Cos[e + f*x
]^n*(b*Tan[e + f*x])^n)/(a*Sin[e + f*x])^n, Int[(a*Sin[e + f*x])^(m + n)/Cos[e + f*x]^n, x], x] /; FreeQ[{a, b
, e, f, m, n}, x] &&  !IntegerQ[n] && (ILtQ[m, 0] || (EqQ[m, 1] && EqQ[n, -2^(-1)]) || IntegersQ[m - 1/2, n -
1/2])

Rule 2639

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticE[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ[{
c, d}, x]

Rubi steps

\begin {align*} \int \frac {\sin ^5(a+b x)}{\sqrt {d \tan (a+b x)}} \, dx &=-\frac {d \sin ^5(a+b x)}{5 b (d \tan (a+b x))^{3/2}}+\frac {7}{10} \int \frac {\sin ^3(a+b x)}{\sqrt {d \tan (a+b x)}} \, dx\\ &=-\frac {7 d \sin ^3(a+b x)}{30 b (d \tan (a+b x))^{3/2}}-\frac {d \sin ^5(a+b x)}{5 b (d \tan (a+b x))^{3/2}}+\frac {7}{20} \int \frac {\sin (a+b x)}{\sqrt {d \tan (a+b x)}} \, dx\\ &=-\frac {7 d \sin ^3(a+b x)}{30 b (d \tan (a+b x))^{3/2}}-\frac {d \sin ^5(a+b x)}{5 b (d \tan (a+b x))^{3/2}}+\frac {\left (7 \sqrt {\sin (a+b x)}\right ) \int \sqrt {\cos (a+b x)} \sqrt {\sin (a+b x)} \, dx}{20 \sqrt {\cos (a+b x)} \sqrt {d \tan (a+b x)}}\\ &=-\frac {7 d \sin ^3(a+b x)}{30 b (d \tan (a+b x))^{3/2}}-\frac {d \sin ^5(a+b x)}{5 b (d \tan (a+b x))^{3/2}}+\frac {(7 \sin (a+b x)) \int \sqrt {\sin (2 a+2 b x)} \, dx}{20 \sqrt {\sin (2 a+2 b x)} \sqrt {d \tan (a+b x)}}\\ &=-\frac {7 d \sin ^3(a+b x)}{30 b (d \tan (a+b x))^{3/2}}-\frac {d \sin ^5(a+b x)}{5 b (d \tan (a+b x))^{3/2}}+\frac {7 E\left (\left .a-\frac {\pi }{4}+b x\right |2\right ) \sin (a+b x)}{20 b \sqrt {\sin (2 a+2 b x)} \sqrt {d \tan (a+b x)}}\\ \end {align*}

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Mathematica [C]  time = 0.87, size = 86, normalized size = 0.80 \[ \frac {\sin (a+b x) \left (28 \tan (a+b x) \sqrt {\sec ^2(a+b x)} \, _2F_1\left (\frac {3}{4},\frac {3}{2};\frac {7}{4};-\tan ^2(a+b x)\right )-20 \sin (2 (a+b x))+3 \sin (4 (a+b x))\right )}{120 b \sqrt {d \tan (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sin[a + b*x]^5/Sqrt[d*Tan[a + b*x]],x]

[Out]

(Sin[a + b*x]*(-20*Sin[2*(a + b*x)] + 3*Sin[4*(a + b*x)] + 28*Hypergeometric2F1[3/4, 3/2, 7/4, -Tan[a + b*x]^2
]*Sqrt[Sec[a + b*x]^2]*Tan[a + b*x]))/(120*b*Sqrt[d*Tan[a + b*x]])

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fricas [F]  time = 0.72, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (\cos \left (b x + a\right )^{4} - 2 \, \cos \left (b x + a\right )^{2} + 1\right )} \sqrt {d \tan \left (b x + a\right )} \sin \left (b x + a\right )}{d \tan \left (b x + a\right )}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^5/(d*tan(b*x+a))^(1/2),x, algorithm="fricas")

[Out]

integral((cos(b*x + a)^4 - 2*cos(b*x + a)^2 + 1)*sqrt(d*tan(b*x + a))*sin(b*x + a)/(d*tan(b*x + a)), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sin \left (b x + a\right )^{5}}{\sqrt {d \tan \left (b x + a\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^5/(d*tan(b*x+a))^(1/2),x, algorithm="giac")

[Out]

integrate(sin(b*x + a)^5/sqrt(d*tan(b*x + a)), x)

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maple [B]  time = 0.54, size = 550, normalized size = 5.14 \[ -\frac {\left (-1+\cos \left (b x +a \right )\right )^{2} \left (12 \sqrt {2}\, \left (\cos ^{6}\left (b x +a \right )\right )-38 \left (\cos ^{4}\left (b x +a \right )\right ) \sqrt {2}-21 \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \cos \left (b x +a \right ) \EllipticF \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {\sqrt {2}}{2}\right )+42 \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \cos \left (b x +a \right ) \EllipticE \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {\sqrt {2}}{2}\right )-21 \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \EllipticF \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {\sqrt {2}}{2}\right )+42 \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \EllipticE \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {\sqrt {2}}{2}\right )+47 \left (\cos ^{2}\left (b x +a \right )\right ) \sqrt {2}-21 \cos \left (b x +a \right ) \sqrt {2}\right ) \left (\cos \left (b x +a \right )+1\right )^{2} \sqrt {2}}{120 b \cos \left (b x +a \right ) \sin \left (b x +a \right )^{4} \sqrt {\frac {d \sin \left (b x +a \right )}{\cos \left (b x +a \right )}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(b*x+a)^5/(d*tan(b*x+a))^(1/2),x)

[Out]

-1/120/b*(-1+cos(b*x+a))^2*(12*2^(1/2)*cos(b*x+a)^6-38*cos(b*x+a)^4*2^(1/2)-21*((-1+cos(b*x+a))/sin(b*x+a))^(1
/2)*((-1+cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2)*((1-cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2)*cos(b*x+a)*Elli
pticF(((1-cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2),1/2*2^(1/2))+42*((-1+cos(b*x+a))/sin(b*x+a))^(1/2)*((-1+cos
(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2)*((1-cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2)*cos(b*x+a)*EllipticE(((1-co
s(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2),1/2*2^(1/2))-21*((-1+cos(b*x+a))/sin(b*x+a))^(1/2)*((-1+cos(b*x+a)+sin(
b*x+a))/sin(b*x+a))^(1/2)*((1-cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2)*EllipticF(((1-cos(b*x+a)+sin(b*x+a))/si
n(b*x+a))^(1/2),1/2*2^(1/2))+42*((-1+cos(b*x+a))/sin(b*x+a))^(1/2)*((-1+cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/
2)*((1-cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2)*EllipticE(((1-cos(b*x+a)+sin(b*x+a))/sin(b*x+a))^(1/2),1/2*2^(
1/2))+47*cos(b*x+a)^2*2^(1/2)-21*cos(b*x+a)*2^(1/2))*(cos(b*x+a)+1)^2/cos(b*x+a)/sin(b*x+a)^4/(d*sin(b*x+a)/co
s(b*x+a))^(1/2)*2^(1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sin \left (b x + a\right )^{5}}{\sqrt {d \tan \left (b x + a\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)^5/(d*tan(b*x+a))^(1/2),x, algorithm="maxima")

[Out]

integrate(sin(b*x + a)^5/sqrt(d*tan(b*x + a)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\sin \left (a+b\,x\right )}^5}{\sqrt {d\,\mathrm {tan}\left (a+b\,x\right )}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sin(a + b*x)^5/(d*tan(a + b*x))^(1/2),x)

[Out]

int(sin(a + b*x)^5/(d*tan(a + b*x))^(1/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sin(b*x+a)**5/(d*tan(b*x+a))**(1/2),x)

[Out]

Timed out

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